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Superposition Principle |
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The
Superposition
Principle
states that in any linear network composed of resistors and voltage
sources, the voltage across a resistor is simply the sum of all the
voltages individually applied to it by each voltage source in the
circuit. The superposition principle is a useful method for
finding the voltage across any resistor in a network where more than one
voltage source is present. A voltage source in this context may
refer to any source of voltage or voltage signal, e.g., power supplies,
batteries, oscillators, signal generators, etc.
To apply the superposition
principle, one has to calculate the individual 'voltage contribution' of
each voltage source to the resistor
of interest. To determine the voltage contribution of a source,
simply 'zero out' all the other sources by replacing them with a short
circuit, or with their
internal resistances if these are known.
Kirchoff's Voltage Law and Ohm's Law are then applied to calculate the
voltage across the resistor with this single source present. Once
all the voltage contributions have been determined, the voltage across
the resistor is simply the sum of all the individual voltages
contributed by the voltage sources.
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Figure 1.
A circuit with two voltage sources; find the voltage across
the 3K resistor |
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Figure 2.
Contribution of the 5V source to the voltage across the 3K
resistor |
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Figure 3.
Contribution
of the 3V source to the voltage across the 3K resistor |
To illustrate
the Superposition Principle, consider the circuit in Figure 1. The
voltage across the 3K resistor may be calculated by getting the
individual voltages applied by the 5V and 4V sources across it. Figure 2 shows the equivalent circuit wherein the 4V
source is 'zeroed out', i.e., replaced by a short circuit. This
circuit gives the voltage V1 applied by the 5V source across the 3K
resistor, wherein V1 = 5V (0.75/2.75) = 1.364 V.
Figure 3
shows the equivalent circuit wherein the 5V source is replaced by a
short circuit. This circuit gives the voltage V2 applied by the 4V
source across the 3K resistor, wherein V2 = 4V (1.2/2.2) = 2.182 V.
Thus, from the Superposition Principle, the voltage across the 3K
resistor in Figure 1 is 1.364V + 2.182V = 3.546V.
Similarly,
the voltage across the 2K resistor is -5V(2/2.75) + 4V(1.2/2.2) = -3.636
+ 2.1818 = -1.454V and the voltage across the 1 K resistor is
5V(.75/2.75) - 4V(1/2.2) = 1.364 - 1.818 = -0.454.
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