The quality of a low-pass filter may be expressed in
terms of its
n-order.
An n-order filter reduces the signal strength by
6n dB
for every octave increase in frequency, i.e., every
time the frequency doubles.
Thus, a
first-order
low-pass filter
(n=1)
will reduce the signal strength by 6 dB every time the frequency doubles.
Mathematically, -6dB = 20 log P2/P1, which yields
P2/P1 = 0.501. This means that a first-order
filter reduces the strength of the signal by about
50% every time the frequency doubles.
As
further illustration, a
second-order
low-pass filter
(n=2) will reduce
the signal strength by 12 dB every time the
frequency of the signal doubles (-12 dB per octave).
Thus, a second-order low-pass filter will reduce a
signal to just 1/4 its original
level every time its frequency increases by an
octave.
Note that in each of the low-pass filters shown
above, the inductors are in series with the input
while the capacitors are in shunt with the input.
This is because the reactance XL of an inductor
increases with the signal frequency, i.e., XL =
2πfL, while the reactance XC of a capacitor
decreases with the signal frequency, i.e., XC = 1 /
2πfC. Thus in these low-pass filters, the
inductors resist the passing of an ac signal as the
frequency increases, while the capacitors shunt them
towards the ground as the frequency increases.
Either way, the effect is to attenuate the
signal as frequency increases.
The following equations apply to the low-pass
filters in Figure 1 above:
1) L = Zo / πf
2) C = 1 / (πf Zo)
3) Zo = sqrt(L/C)
4) f = 1 / (π sqrt(LC))
where Zo is the line impedance and f is the cut-off
frequency of the filter.